Dear @ghuser

If you create a method that returns something other than an Observable, it's not an operator, and that's fine.

IMHO the whole sentence is useless. :D

What you should fouse about is:

• creation of Observable
• creation of OperatorFunction

Observable:

Static:

const arr = [1,2,3,4];
const o = new Observable((subscriber => {
  arr.foeEach(n => subscriber.next(n))
  subscriber.complete()
}));

Creation Function:

const arr = [1,2,3,4];
function createObserfableFromArray(arr) => {
  return new Observable((subscriber => {
    arr.foeEach(n => subscriber.next(n))
    subscriber.complete()
  }));
}
const o =createObserfableFromArray = (arr) ;

Operators

Static:

function log(observable) => {
  return observable.pipe(tap(value => console.log(value)));
}

observable.pipe(
  log
)

Creation Function:

function logCreation(param) {
  return function(observable) => {
    return observable.pipe(
     tap(value => console.log(param, value))
   );
  }
}

observable.pipe(
  logCreation('value: ')
)

To sum up:

Operators are functions that take an Observable and return an observable:

• (o: Observable) => Observable
  If you wrap them in a function to create them they are configurable:
• (cfg) => (o: Observable) => Observable

Observables can be created by using instantiating a new one:

• new Observable
  or by a function:
• (arg?: any) => Observable

Let me know if this helps.

Best,
Michael

Thank you so much, @BioPhoton!! @ghuser, does that help you? We can also clear up the docs on this point.

@BioPhoton

It is more clear now, though this syntax confuses me. Is it valid js?:

function createObserfableFromArray(arr) => {

and

const o =createObserfableFromArray = (arr) ;

Status: Docs Team can use the excellent explanation by @BioPhoton to update the documentation.